Solución
$$\begin{aligned}
\bold{u}\cdot(\bold{v}\times\bold{w}) &= \begin{vmatrix} 1 & 3 & 5\\ 2 & -1 & 0\\-3 & 0 & -1\end{vmatrix}\\
&= 1\begin{vmatrix} -1 & 0\\ 0 & -1\end{vmatrix} -3\begin{vmatrix} 2 & 0\\ -3 & -1\end{vmatrix} + 5\begin{vmatrix} 2 & -1\\ -3 & 0\end{vmatrix}\\
&= (1−0)−3(−2−0)+5(0−3)\\
&= 1+6−15=−8
\end{aligned}$$