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<h1>Solución</h1>

$$\mathop {\lim }\limits_{x \to 6} {{3x - 18} \over {2x - 12}} = {{18 - 18} \over {12 - 12}} = {0 \over 0}$$
<p>Así,
$$\mathop {\lim }\limits_{x \to 6} {{3x - 18} \over {2x - 12}} = \mathop {\lim }\limits_{t \to 9} {{3\left( {x - 6} \right)} \over {2\left( {x - 6} \right)}} = {3 \over 2}$$
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